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LED5000 Scheda tecnica(PDF) 18 Page - STMicroelectronics

Il numero della parte LED5000
Spiegazioni elettronici  3 A monolithic step-down current source with dimming capability
PDF  52 Pages
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Produttore elettronici  STMICROELECTRONICS [STMicroelectronics]
Homepage  http://www.st.com
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LED5000 Scheda tecnica(HTML) 18 Page - STMicroelectronics

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Application notes - buck conversion
LED5000
18/51
Doc ID 023951 Rev 1
With the power components selected in accordance with
Chapter 5.9: Component selection
and given the BW specification, the components composing the compensation network can
be calculated as:
Equation 16
where the term mC is represented in Equation 4, RLOAD the equivalent loading resistor
(
Equation 12), RS the sensing resistor value, Gm the error amplifier transconductance and
RCS the current sense gain (Table 5: Electrical characteristics)
Equation 17
where K represents the leading position of the FZ (Equation 11) with respect to the system
bandwidth. In general, a value of 2 gives enough phase margin to the overall small loop
transfer function.
5.7
Example of system design
Design specification:
VIN=48 V, VFW_LED=3.7 V, nLED= 10, rLED= 1.1 W, ILED= 1 A, ILED RIPPLE= 2%
The inductor and capacitor value are dimensioned to meet the ILED RIPPLE specification (see
Chapter 5.9.2 for output capacitor and inductor selection guidelines):
L=22
μH, COUT=1.0 μF mlcc (negligible ESR)
In accordance with
Chapter 5.9.1 the sensing resistor value is:
Equation 18
Assuming a system bandwidth of:
Equation 19
the ideal values of the components making up the compensation network is:
Equation 20
Final component selection is based on commercial values and a small capacitor CP is
added to reduce noise at the error amplifier output. CP slightly decreases the BW and phase
margin.
R
C
1
R
LOAD
T
SW
⋅
L
------------------------------------
m
C
1D
–
() 0.5
–
⋅
[]
⋅
+
f
P
-----------------------------------------------------------------------------------------------------------
BW
R
CS
⋅
G
m
R
S
⋅
----------------------------
⋅
=
C
C
K
R
C
BW
⋅
------------------------
=
R
S
200 mV
1 A
--------------------
200 m
Ω
==
BW
70 kHz
BW
MAX
<
=
R
C
43 k
Ω
=
C
C
650 pF
=



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