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AN443 Scheda tecnica(PDF) 10 Page - STMicroelectronics

Il numero della parte AN443
Spiegazioni elettronici  SERIES OPERATION OF FAST RECTIFIERS
PDF  14 Pages
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Produttore elettronici  STMICROELECTRONICS [STMicroelectronics]
Homepage  http://www.st.com
Logo STMICROELECTRONICS - STMicroelectronics

AN443 Scheda tecnica(HTML) 10 Page - STMicroelectronics

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AN443 APPLICATION NOTE
10/14
V1 < VRRM
Generally, the value of the junction capacitance at the operating voltage is very close to the value at VRRM
(CJ1) so we can write
This condition can be met by using very fast rectifiers in applications where the dIF/dt is low (like in some
resonant converters or flyback converters) and consequently low QRR.
EQUALIZATION BY TRANSIL DIODES
TRANSIL diodes are avalanche diodes designed for operation in breakdown characteristic and they are
used as clamping devices in a wide field of applications. To limit the voltage across the rectifiers of a string
below the maximum value, TRANSIL diodes can be used according to diagram in Figure 12.
Figure 12. Voltage sharing by TRANSIL diodes
TRANSIL operates as a voltage limiter at steady state, during the switching phase, and also in case of
external voltage transients.
Steady state
In the blocking condition, the TRANSILS connected across the diode D1 (which has the lowest reverse
current) operate in the breakdown characteristic. The current through these TRANSILS is IR and the pow-
er dissipation is:
VBR
.
∆IR . δ
(
δ = duty cycle)
Where VBR is the maximum breakdown voltage of TRANSILS. In general this extra power dissipation is
lower than in the case of sharing by resistors and TRANSILS in axial packages can be used.
Switching phase
When the fastest diodes of the string switches off, the TRANSILS across it operate in breakdown charac-
teristic, and the reverse recovery current of the other diodes flows through these TRANSILS. The charge
remaining in the string at this moment is:
(n-1)
∆QRR
and we can estimate the maximum energy in the TRANSILS with
E < 1/2(n-1) .
∆QRR . VBR
This relation does not take into account the losses due to the capacitive current through the string.
∆Q
RR
V
RRM CJ1 n1
–
() C
Jn
+
[] V
MCJn
–
n1
–
-----------------------------------------------------------------------------------------
<
∆Q
RR
C
J1 nVRRM
V
M
–
()
n1
–
------------------------------------------------
<
D1
D2
D3
Dn
+VM



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