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LTC1702IGN Scheda tecnica(PDF) 19 Page - Linear Technology |
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LTC1702IGN Scheda tecnica(HTML) 19 Page - Linear Technology |
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19 / 36 page ![]() 19 LTC1702 APPLICATIONS INFORMATION from CIN (time point A). 50% of the way through, TG2 turns on and the total current is 13A (time point B). Shortly thereafter, TG1 turns off and the current drops to 10A (time point C). Finally, TG2 turns off and the current spends a short time at 0 before TG1 turns on again (time point D). IA A AA A AVG = ()+()+ ()+()= 30 5 130 16 10 016 0 018 5 18 •. •. •. •. . Now we can calculate the RMS current. Using the same waveform we used to calculate the average DC current, subtract the average current from each of the DC values. Square each current term and multiply the squares by the same period percentages we used to calculate the aver- age DC current. Sum the results and take the square root. The result is the approximate RMS current as seen by the input capacitor with both sides of the LTC1702 at full load. Actual RMS current will differ due to inductor ripple cur- rent and resistive losses, but this approximate value is adequate for input capacitor calculation purposes. TIME 0A B C D 50% 16% 16% 18% – 5.2 0 –2.2 4.8 7.8 1702 SB2 Figure SB2. AC Current Calculation I A RMS RMS = () + ()+ ()+() = –. • . . • . .• . – . • . . 218 0 5 7 82 016 482 0 16 518 0 18 455 22 22 If the circuit is likely to spend time with one side operating and the other side shut down, the RMS current will need to be calculated for each possible case (side 1 on, side 2 off; side 1 off, side 2 on; both sides on). The capacitor must be sized to withstand the largest RMS current of the three—sometimes this occurs with one side shut down! Side only IA A A IA Side only IA A A I AVE RMS RMS AVE RMS 1 3 0 67 0 0 33 2 01 1 0 67 2 0 33 1 42 2 10 032 0 068 3 2 68 032 3 2 0 68 1 1 22 2 2 22 : •. •. . •. – • . . : •. •. . .• . – . • . = ()+()= = ()+()= = ()+()= = ()+() = 4466 4 55 .. AA RMS RMS > Consider the case where both sides are operating at the same load, with a 50% duty cycle at each side. The RMS current with both sides running is near zero, while the RMS current with one side active is 1/2 the total load current of that side. The 2-phase, 5V to 2.5V circuit in the applications section takes advantage of this phenom- enon, allowing it to supply 40A of output current with only 120 µF of input capacitance (and only 40µF of output capacitance!). only 10A, requiring the same 0.01 Ω ESR rating. As long as the capacitor we chose for the single side application can support the slightly higher 4.8ARMS current, we can add the second channel without changing the input capacitor at all. As a general rule, an input bypass capacitor capable of supporting the larger output current channel can sup- port both channels running simultaneously (see the 2-Phase Operation section for more details). Tantalum capacitors are a popular choice as input capaci- tors for LTC1702 applications, but they deserve a special caution here. Generic tantalum capacitors have a destruc- tive failure mechanism when they are subjected to large RMS currents (like those seen at the input of a LTC1702). At some random time after they are turned on, they can blow up for no apparent reason. The capacitor manufac- turers are aware of this and sell special “surge tested” |
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