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SIC401DB Scheda tecnica(PDF) 21 Page - Vishay Siliconix |
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SIC401DB Scheda tecnica(HTML) 21 Page - Vishay Siliconix |
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21 / 30 page ![]() SiC401A, SiC401BCD www.vishay.com Vishay Siliconix S20-0483-Rev. E, 29-Jun-2020 21 Document Number: 63835 For technical questions, contact: powerictechsupport@vishay.com THIS DOCUMENT IS SUBJECT TO CHANGE WITHOUT NOTICE. THE PRODUCTS DESCRIBED HEREIN AND THIS DOCUMENT ARE SUBJECT TO SPECIFIC DISCLAIMERS, SET FORTH AT www.vishay.com/doc?91000 Assuming a peak voltage VPEAK of 1.65 V (150 mV rise upon load release), and a 15 A load release, the required capacitance is shown by the next equation. During the load release time, the voltage cross the inductor is approximately - VOUT. This causes a down-slope or falling di/dt in the inductor. If the load dI/dt is not much faster than the dI/dt of the inductor, then the inductor current will tend to track the falling load current. This will reduce the excess inductive energy that must be absorbed by the output capacitor; therefore a smaller capacitance can be used. The following can be used to calculate the needed capacitance for a given dILOAD/dt. Peak inductor current is shown by the next equation. ILPK = Imax. + 1/2 x IRIPPLE max. ILPK = 10 + 1/2 x 4.43 = 12.215 A Imax. = maximum load release = 15 A Example This would cause the output current to move from 15 A to 0 A in 4 μs, giving the minimum output capacitance requirement shown in the following equation. Note that COUT is much smaller in this example, 169 μF compared to 316 μF based on a worst case load release. To meet the two design criteria of minimum 316 μF and maximum 10.2 mW ESR, select one capacitor of 330 μF and 9 mW ESR. Stability Considerations Unstable operation is possible with adaptive on-time controllers, and usually takes the form of double-pulsing or ESR loop instability. Double-pulsing occurs due to switching noise seen at the FB input or because the FB ripple voltage is too low. This causes the FB comparator to trigger prematurely after the 250 ns minimum off-time has expired. In extreme cases the noise can cause three or more successive on-times. Double-pulsing will result in higher ripple voltage at the output, but in most applications it will not affect operation. This form of instability can usually be avoided by providing the FB pin with a smooth, clean ripple signal that is at least 10 mVp-p, which may dictate the need to increase the ESR of the output capacitors. It is also imperative to provide a proper PCB layout as discussed in the Layout Guidelines section. Another way to eliminate doubling-pulsing is to add a small (~ 10 pF) capacitor across the upper feedback resistor, as shown in Fig. 13. This capacitor should be left unpopulated until it can be confirmed that double-pulsing exists. Adding the CTOP capacitor will couple more ripple into FB to help eliminate the problem. An optional connection on the PCB should be available for this capacitor. Fig. 13 - Capacitor Coupling to FB Pin ESR loop instability is caused by insufficient ESR. The details of this stability issue are discussed in the ESR Requirements section. The best method for checking stability is to apply a zero-to-full load transient and observe the output voltage ripple envelope for overshoot and ringing. Ringing for more than one cycle after the initial step is an indication that the ESR should be increased. ESR Requirements A minimum ESR is required for two reasons. One reason is to generate enough output ripple voltage to provide 10 mVp-p at the FB pin (after the resistor divider) to avoid double-pulsing. The second reason is to prevent instability due to insufficient ESR. The on-time control regulates the valley of the output ripple voltage. This ripple voltage is the sum of the two voltages. One is the ripple generated by the ESR, the other is the ripple due to capacitive charging and discharging during the switching cycle. For most applications the minimum ESR ripple voltage is dominated by the output capacitors, typically SP or POSCAP devices. For stability the ESR zero of the output capacitor should be lower than approximately one-third the switching frequency. The formula for minimum ESR is shown by the following COUT_min. = 1 µH (10 + x 4.43)2 (1.65)2 - (1.5)2 COUT_min. = 316 µF 1 2 Rate of change of load current = dILOAD dt COUT = ILPK x L x - x dt 2 (VPK - VOUT) ILPK VOUT Imax. dlLOAD dlLOAD dt = 2.5 A 1 µs COUT = 12.215 x 1 µH x - x 1 µs 2 (1.65 - 1.5) 12.215 1.5 10 2.5 COUT = 169 µF VOUT R1 R2 To FB pin CTOP |
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