(-10.9 mV /

V =

T + 2103 mV

(-10.9 mV /

V - 1885 mV =

(T - 20

1558 mV - 1885 mV

50

u

¹

·

V - 1885 mV =

(T - 20

u

¹

·

30

)

00347

.

0

(

2

mV

V

3

.

1777

00347

.

0

4

888

.

10

888

.

10

T

TEMP

2

u

u

u

ª

º

ª

º

«

»

«

»

¬

¼ ¬

¼

2

TEMP

2

mV

mV

V

mV = 1777.3mV - 10.888

T - 30°C

- 0.00347

T - 30°C

°C

°C

LMT86, LMT86-Q1

www.ti.com

SNIS169C – MARCH 2013 – REVISED OCTOBER 2015

Feature Description (continued)

Table 1. LMT86 and LMT86-Q1 Transfer Table (continued)

TEMP

TEMP

TEMP

TEMP

TEMP

(°C)

(mV)

(°C)

(mV)

(°C)

(mV)

(°C)

(mV)

(°C)

(mV)

-32

2439

8

2014

48

1580

88

1133

128

676

-31

2429

9

2004

49

1569

89

1122

129

665

-30

2418

10

1993

50

1558

90

1110

130

653

-29

2408

11

1982

51

1547

91

1099

131

642

-28

2397

12

1971

52

1536

92

1088

132

630

-27

2387

13

1961

53

1525

93

1076

133

618

-26

2376

14

1950

54

1514

94

1065

134

607

-25

2366

15

1939

55

1503

95

1054

135

595

-24

2355

16

1928

56

1492

96

1042

136

584

-23

2345

17

1918

57

1481

97

1031

137

572

-22

2334

18

1907

58

1470

98

1020

138

560

-21

2324

19

1896

59

1459

99

1008

139

549

-20

2313

20

1885

60

1448

100

997

140

537

-19

2302

21

1874

61

1436

101

986

141

525

-18

2292

22

1864

62

1425

102

974

142

514

-17

2281

23

1853

63

1414

103

963

143

502

-16

2271

24

1842

64

1403

104

951

144

490

-15

2260

25

1831

65

1391

105

940

145

479

-14

2250

26

1820

66

1380

106

929

146

467

-13

2239

27

1810

67

1369

107

917

147

455

-12

2228

28

1799

68

1358

108

906

148

443

-11

2218

29

1788

69

1346

109

895

149

432

150

420

Although the LMT86 and LMT86-Q1 is very linear, its response does have a slight umbrella parabolic shape.

This shape is very accurately reflected in Table 1. The Transfer Table can be calculated by using the parabolic

equation.

(1)

The parabolic equation is an approximation of the transfer table and the accuracy of the equation degrades

slightly at the temperature range extremes. Equation 1 can be solved for T resulting in:

(2)

For an even less accurate linear transfer function approximation, a line can easily be calculated over the desired

temperature range from the Table using the two-point equation:

(3)

coordinates of the highest temperature.

For example, if we want to resolve this equation, over a temperature range of 20°C to 50°C, we would proceed

as follows:

(4)

(5)

(6)

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